Given a binary tree containing digits from
0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path
1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path
The root-to-leaf path
1->2 represents the number 12.The root-to-leaf path
1->3 represents the number 13.
Return the sum = 12 + 13 =
25.
My Code:
int sumNumbers(TreeNode *root) {
if(!root) return 0;
queue q;
q.push(root);
int sum = 0;
while(!q.empty()){
TreeNode* cur = q.front();
if(!cur->left && !cur->right){
sum = sum + cur->val;
}
else{
if(cur->left){
cur->left->val = cur->val*10 + cur->left->val;
q.push(cur->left);
}
if(cur->right){
cur->right->val = cur->val*10 + cur->right->val;
q.push(cur->right);
}
}
q.pop();
}
return sum;
}
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